Bloomberg Medium csharp

Partition Equal Subset Sum

Animated walkthrough

Step through the algorithm visually — use Play or the step buttons (inspired by AlgoMaster / visualgo).

Step 1 / 1

Bloomberg interview context: Partition Equal Subset Sum is a Medium 1-D Dynamic Programming problem — Define state dp[i] and transition from smaller subproblems.

Use the animation above to step through each move before writing code.

Pattern: 1-D Dynamic Programming

Read from stdin, write to stdout. Classic interview problem #416.

Problem

Partition Equal Subset Sum — Bloomberg interview prep · 1-D Dynamic Programming

Classic interview problem #416.

Input (stdin)

Line 1: n

Output (stdout)

DP 1D (Partition Equal Subset Sum)

Your program must read from stdin and write the answer to stdout (no extra debug text).

Examples

Sample
Input
10
Output
89
Hints
  • Input format: Line 1: n
  • DSA Interview 150 — 1-D Dynamic Programming
  • Problem #416
  • Frequently asked at Bloomberg
  • 1-D Dynamic Programming

Your solution

TestStatusDetails
Ready — edit the code above and click Run or Submit.

Solution

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

class Program
{
    static int[] Ria(string line = null)
    {
        line ??= Console.ReadLine();
        if (string.IsNullOrWhiteSpace(line)) return Array.Empty<int>();
        return line.Trim().Split(new[] { ' ', ',', '\t' }, StringSplitOptions.RemoveEmptyEntries)
            .Select(int.Parse).ToArray();
    }
    static string[] Rsa()
    {
        int n = int.Parse(Console.ReadLine());
        var arr = new string[n];
        for (int i = 0; i < n; i++) arr[i] = Console.ReadLine();
        return arr;
    }
    static void W(params object[] parts) => Console.WriteLine(string.Join(" ", parts));
    static void Wb(bool v) => Console.WriteLine(v ? "true" : "false");
    static void Wi(int v) => Console.WriteLine(v);
    static void Ws(string v) => Console.WriteLine(v);

    static void Main()
    {
int n = int.Parse(Console.ReadLine());
int a = 1, b = 1;
for (int i = 2; i <= n; i++) { int t = a + b; a = b; b = t; }
Wi(b);
    }
}

Try solving on your own first, then reveal the official answer.

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