Persistent Systems Medium csharp

Best Time to Buy and Sell Stock with Cooldown

Animated walkthrough

Step through the algorithm visually — use Play or the step buttons (inspired by AlgoMaster / visualgo).

Step 1 / 1

Persistent Systems interview context: Best Time to Buy and Sell Stock with Cooldown is a Medium 2-D Dynamic Programming problem — Grid DP: dp[row][col] often means paths or min cost to reach a cell.

Use the animation above to step through each move before writing code.

Pattern: 2-D Dynamic Programming

Read from stdin, write to stdout. Classic interview problem #309.

Problem

Best Time to Buy and Sell Stock with Cooldown — Persistent Systems interview prep · 2-D Dynamic Programming

Classic interview problem #309.

Input (stdin)

Line 1: m\nLine 2: n

Output (stdout)

DP 2D grid paths (Best Time to Buy and Sell Stock with Cooldown)

Your program must read from stdin and write the answer to stdout (no extra debug text).

Examples

Sample
Input
3
7
Output
28
Hints
  • Input format: Line 1: m\nLine 2: n
  • DSA Interview 150 — 2-D Dynamic Programming
  • Problem #309
  • Frequently asked at Persistent Systems
  • 2-D Dynamic Programming

Your solution

TestStatusDetails
Ready — edit the code above and click Run or Submit.

Solution

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

class Program
{
    static int[] Ria(string line = null)
    {
        line ??= Console.ReadLine();
        if (string.IsNullOrWhiteSpace(line)) return Array.Empty<int>();
        return line.Trim().Split(new[] { ' ', ',', '\t' }, StringSplitOptions.RemoveEmptyEntries)
            .Select(int.Parse).ToArray();
    }
    static string[] Rsa()
    {
        int n = int.Parse(Console.ReadLine());
        var arr = new string[n];
        for (int i = 0; i < n; i++) arr[i] = Console.ReadLine();
        return arr;
    }
    static void W(params object[] parts) => Console.WriteLine(string.Join(" ", parts));
    static void Wb(bool v) => Console.WriteLine(v ? "true" : "false");
    static void Wi(int v) => Console.WriteLine(v);
    static void Ws(string v) => Console.WriteLine(v);

    static void Main()
    {
int m = int.Parse(Console.ReadLine());
int n = int.Parse(Console.ReadLine());
int[] dp = new int[n];
Array.Fill(dp, 1);
for (int i = 1; i < m; i++)
    for (int j = 1; j < n; j++)
        dp[j] += dp[j - 1];
Wi(dp[n - 1]);
    }
}

Try solving on your own first, then reveal the official answer.

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