Palindrome Partitioning (minimum cuts)?

Short answer: int MinCutPalindromePartition(string s) { int n = s.Length; bool[,] dp = new bool[n, n]; int[] cuts = new int[n]; for (int i = 0; i < n; i++) { int minCuts = i; for (int j = 0; j <= i; j++) { if (s[j] == s[i] && (i - j < 2 || dp[j + 1, i - 1])) { dp[j, i] = true; minCuts = j == 0 ? 0 : Math.Min(minCuts, cuts[j - 1] + 1); } } cuts[i] = minCuts; } return cuts[n - 1]; }

Example code

int MinCutPalindromePartition(string s) {
int n = s.Length;
bool[,] dp = new bool[n, n];
int[] cuts = new int[n];
for (int i = 0; i < n; i++) {
int minCuts = i;
for (int j = 0; j <= i; j++) {
if (s[j] == s[i] && (i - j < 2 || dp[j + 1, i - 1])) {
dp[j, i] = true; minCuts = j == 0 ? 0 : Math.Min(minCuts, cuts[j - 1] + 1); }
}
cuts[i] = minCuts;
}
return cuts[n - 1];
}

Real-world example (ShopNest)

In coding rounds, state complexity aloud, write a clear ShopNest-flavored example (orders, carts), then handle edge cases (empty list, null, overflow).

Say this in the interview

1. Define — one clear sentence (the short answer above).
2. Example — relate it to a project like ShopNest or your real work.
3. Trade-off — when you would not use it.