Mid From PDF LINQ LINQ

Find names of employees with even-length names .Where(e => e.Name.Length % 2 == 0)?

Short answer: var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name);

Example code

var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name);

Real-world example (ShopNest)

ShopNest filters active products with products.Where(p => p.IsActive && p.Stock > 0) before showing the catalog.

Say this in the interview

  1. Define — one clear sentence (the short answer above).
  2. Example — relate it to a project like ShopNest or your real work.
  3. Trade-off — when you would not use it.
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