Find names of employees with even-length names .Where(e => e.Name.Length % 2 == 0)?
Short answer: var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name);
Example code
var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name); var evenNames = employees .Select(e => e.Name);
Real-world example (ShopNest)
ShopNest filters active products with products.Where(p => p.IsActive && p.Stock > 0) before showing the catalog.
Say this in the interview
- Define — one clear sentence (the short answer above).
- Example — relate it to a project like ShopNest or your real work.
- Trade-off — when you would not use it.
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